--- a/src/misc/RingFinder.cc Wed Mar 12 16:21:49 2014 +0200
+++ /dev/null Thu Jan 01 00:00:00 1970 +0000
@@ -1,169 +0,0 @@
-/*
- * LDForge: LDraw parts authoring CAD
- * Copyright (C) 2013, 2014 Santeri Piippo
- *
- * This program is free software: you can redistribute it and/or modify
- * it under the terms of the GNU General Public License as published by
- * the Free Software Foundation, either version 3 of the License, or
- * (at your option) any later version.
- *
- * This program is distributed in the hope that it will be useful,
- * but WITHOUT ANY WARRANTY; without even the implied warranty of
- * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
- * GNU General Public License for more details.
- *
- * You should have received a copy of the GNU General Public License
- * along with this program. If not, see <http://www.gnu.org/licenses/>.
- */
-
-#include "RingFinder.h"
-#include "../Misc.h"
-
-RingFinder g_RingFinder;
-
-// =============================================================================
-//
-bool RingFinder::findRingsRecursor (double r0, double r1, Solution& currentSolution)
-{
- // Don't recurse too deep.
- if (m_stack >= 5)
- return false;
-
- // Find the scale and number of a ring between r1 and r0.
- assert (r1 >= r0);
- double scale = r1 - r0;
- double num = r0 / scale;
-
- // If the ring number is integral, we have found a fitting ring to r0 -> r1!
- if (isInteger (num))
- {
- Component cmp;
- cmp.scale = scale;
- cmp.num = (int) round (num);
- currentSolution.addComponent (cmp);
-
- // If we're still at the first recursion, this is the only
- // ring and there's nothing left to do. Guess we found the winner.
- if (m_stack == 0)
- {
- m_solutions.push_back (currentSolution);
- return true;
- }
- }
- else
- {
- // Try find solutions by splitting the ring in various positions.
- if (isZero (r1 - r0))
- return false;
-
- double interval;
-
- // Determine interval. The smaller delta between radii, the more precise
- // interval should be used. We can't really use a 0.5 increment when
- // calculating rings to 10 -> 105... that would take ages to process!
- if (r1 - r0 < 0.5)
- interval = 0.1;
- else if (r1 - r0 < 10)
- interval = 0.5;
- else if (r1 - r0 < 50)
- interval = 1;
- else
- interval = 5;
-
- // Now go through possible splits and try find rings for both segments.
- for (double r = r0 + interval; r < r1; r += interval)
- {
- Solution sol = currentSolution;
-
- m_stack++;
- bool res = findRingsRecursor (r0, r, sol) && findRingsRecursor (r, r1, sol);
- m_stack--;
-
- if (res)
- {
- // We succeeded in finding radii for this segment. If the stack is 0, this
- // is the first recursion to this function. Thus there are no more ring segments
- // to process and we can add the solution.
- //
- // If not, when this function ends, it will be called again with more arguments.
- // Accept the solution to this segment by setting currentSolution to sol, and
- // return true to continue processing.
- if (m_stack == 0)
- m_solutions.push_back (sol);
- else
- {
- currentSolution = sol;
- return true;
- }
- }
- }
-
- return false;
- }
-
- return true;
-}
-
-// =============================================================================
-// Main function. Call this with r0 and r1. If this returns true, use bestSolution
-// for the solution that was presented.
-//
-bool RingFinder::findRings (double r0, double r1)
-{
- m_solutions.clear();
- Solution sol;
-
- // Recurse in and try find solutions.
- findRingsRecursor (r0, r1, sol);
-
- // Compare the solutions and find the best one. The solution class has an operator>
- // overload to compare two solutions.
- m_bestSolution = null;
-
- for (QVector<Solution>::iterator solp = m_solutions.begin(); solp != m_solutions.end(); ++solp)
- {
- const Solution& sol = *solp;
-
- if (m_bestSolution == null || sol.isSuperiorTo (m_bestSolution))
- m_bestSolution = /
- }
-
- return (m_bestSolution != null);
-}
-
-// =============================================================================
-//
-bool RingFinder::Solution::isSuperiorTo (const Solution* other) const
-{
- // If this solution has less components than the other one, this one
- // is definitely better.
- if (getComponents().size() < other->getComponents().size())
- return true;
-
- // vice versa
- if (other->getComponents().size() < getComponents().size())
- return false;
-
- // Calculate the maximum ring number. Since the solutions have equal
- // ring counts, the solutions with lesser maximum rings should result
- // in cleaner code and less new primitives, right?
- int maxA = 0,
- maxB = 0;
-
- for (int i = 0; i < getComponents().size(); ++i)
- {
- maxA = max (getComponents()[i].num, maxA);
- maxB = max (other->getComponents()[i].num, maxB);
- }
-
- if (maxA < maxB)
- return true;
-
- if (maxB < maxA)
- return false;
-
- // Solutions have equal rings and equal maximum ring numbers. Let's
- // just say this one is better, at this point it does not matter which
- // one is chosen.
- return true;
-}
\ No newline at end of file